Today, as soon as I arrived, I was
put to work as to making the two buffers. Applying the knowledge that I learned
last week—about finding the correct calculations pertaining to the measurement
of the particular substance—, I was asked to find the target amount. When last
week, I dealt with a liquid (though only hypothetical because I didn’t actually
get to create the mixture), this week, I prepared a buffer using solids: Na4O7P2
(446.06 Mw) and H2Na2O7P2 (221.94
Mw). Wanting a total volume of 20mL in each of the two buffers that I was going
to prepare, I found the weight of the former and latter solutions needed in
grams. To do this I used the formula: weight of solute (g)= formula weight of
solute (g/mol) x molarity (mol/L) x final volume (L). After finding the
measurements 1.7624g and 0.8878g respectively, all was left for me to do was
put combine the various components into their vials.

In a broader scope, this pertains
to the entire goal of capillary electrophoresis (electrophoresis separates
macromolecules by size, charge, and/or properties) as a buffer is needed for
the conduction of charge. This charge is transmitted by the ions provided by
the buffer. In addition, “the buffer, by providing a reservoir of weak acid and
base, also keeps the pH within a narrow range. This is important because the
structure and charge of a protein or nucleic acid will change if subjected to
significant pH changes, thus preventing proper separation.”
Next week, my mentor and I are
hoping that the substance will have dissolved and then go from there to
continue what we left unfinished today.
The Purpose of Buffer in Electrophoresis. Retrieved from
http://www.ehow.com/about_6613320_purpose-buffer-electrophoresis.html.